C Programs

Predict the output of the following Programs

---

#include 〈stdio.h〉
#include 〈time.h〉
int

a[1817];main(z,p,q,r){for(p=80;q+p-80;p-=2*a[p])for(z=9;z--;)q=3&(r=time(0)+r*57)/7,q=q?q-1?

q-2?1-p%79?-1:0:p%79-77?1:0:p<1659?79:0:p>158?-79:0,q?!a[p+q*2]?a[p+=a[p+=q]=q]=q:0:0;for(;q

++-1817;)printf(q%79?"%c":"%c\n"," #"[!a[q-1]]);}



//Above programs make a maze ,Evey Time you compile it gives new maze.

---

#include 〈stdio.h〉
#include 〉conio.h〉

_(__,___,____){___/__<=1?_(__,___+1,____):!(___%__)?_(__,___+1,0):___%__==___/

__&&!____?(printf("%d\t",___/__),_(__,___+1,0)):___%__>1&&___%__<___/__?_(__,1+>

---

#include 〈stdio.h〉
#include 〈stdlib.h〉
#include 〈string.h〉
#include 〈time.h〉
#define ch(x) "/|\\"[sgn(x)+1]
#define sgn(x) (x>0?1:x?-1:0)
main(){long a=0,b=0,c=0,d=0,i=0,j=0;char s[21][40]
;memset(s,' ',0x348);while(j++<0x15)s[j][-1]='\0'; d="18-~!c,c="-sgn(a)+d">>3;break;
case 3:c=a=(c>0?1:-1)*(d=b=18);break;
case 4:c=a=sgn(a)*(d=b*=7.0/9);break;
case 5:sgn(c)*c>2&&(c-=3*sgn(c),d--);
}s[d][19+c]=ch(c);}while(i&21^21)puts(s[31&i++]);}

---

#include 〈stdio.h〉

m(f,a,s)char*s;
{char c;return f&1?a!=*s++?m(f,a,s):s[11]:f&2?a!=*s++?1+m(f,a,s):1:f&4?a--?
putchar(*s),m(f,a,s):a:f&8?*s?m(8,32,(c=m(1,*s++,"Arjan Kenter. \no$../.\""),
m(4,m(2,*s++,"POCnWAUvBVxRsoqatKJurgXYyDQbzhLwkNjdMTGeIScHFmpliZEf"),&c),s)):
65:(m(8,34,"rgeQjPruaOnDaPeWrAaPnPrCnOrPaPnPjPrCaPrPnPrPaOrvaPndeOrAnOrPnOrP\
nOaPnPjPaOrPnPrPnPrPtPnPrAaPnBrnnsrnnBaPeOrCnPrOnCaPnOaPnPjPtPnAaPnPrPnPrCaPn\
BrAnxrAnVePrCnBjPrOnvrCnxrAnxrAnsrOnvjPrOnUrOnornnsrnnorOtCnCjPrCtPnCrnnirWtP\
nCjPrCaPnOtPrCnErAnOjPrOnvtPnnrCnNrnnRePjPrPtnrUnnrntPnbtPrAaPnCrnnOrPjPrRtPn\
CaPrWtCnKtPnOtPrBnCjPronCaPrVtPnOtOnAtnrxaPnCjPrqnnaPrtaOrsaPnCtPjPratPnnaPrA\
aPnAaPtPnnaPrvaPnnjPrKtPnWaOrWtOnnaPnWaPrCaPnntOjPrrtOnWanrOtPnCaPnBtCjPrYtOn\
UaOrPnVjPrwtnnxjPrMnBjPrTnUjP"),0);}

main(){return m(0,75,"mIWltouQJGsBniKYvTxODAfbUcFzSpMwNCHEgrdLaPkyVRjXeqZh");}

---

int main(void)
{
int a,b,c;
int count = 1;
for (b=c=10;a=
"- LLLLLL?, LMKC,XYZHELLO FOLKS,\
TFy!QJu ROo TNn(ROo)SLq SLq ULo+\
UHs UJq TNn*RPn/QPbEWS_JSWQAIJO^\
NBELPeHBFHT}TnALVlBLOFAkHFOuFETp\
HCStHAUFAgcEAelclcn^r^r\\tZvYxXy\
T|S~Pn SPm SOn TNn ULo0ULo#ULo-W\
Hq!WFs XDt!" [b+++21];)
for(; a-- > 64 ; )
putchar ( ++c=='Z' ? c = c/ 9:33^b&1);
getchar(); }

---

#include 〈stdio.h〉

void main()
{
int i;
clrscr();
i=printf("ABC");
printf("\n%d",i);//beacuse printf function returns value indicating that it print 3 values.
}

---

void main()
{
printf("%d",076);
}

/*printf("%d",076); the value 76 taken as octal value because 076 is the representation of

octal 76. So the decimal value of 76 is 62.*/

---

void main()
{
int a[4]={[1]1,[2]2};
printf("%d%d%d%d",a[0],a[1],a[2],a[3]);
}

Ans:-0120

---

#define fun(s,t,u,m,p,e,d)m##s##u##t
#define begen fun(a,n,i,m,a,t,e)
#include
void begen()
{
clrscr();
printf("sss");
}

---

#include 〈stdio.h〉
#include 〈conio.h〉

int main(void)
{
char *string = "NotMyStuFF.BlogspoT";

printf("string prior to strlwr: %s\n", string);
strupr(string);
printf("string after strlwr: %s\n", string);
return 0;
}

---

#include 〈stdio.h〉
#include 〈conio.h〉

int main(void)
{
char *string = "NotMyStuFF.BlogspoT";

printf("string prior to strlwr: %s\n", string);
strlwr(string);
printf("string after strlwr: %s\n", string);
return 0;
}

---

void change (int *r,int s)
{
*r = 100;
s = 200;
}
void main ()
{
int k, m;
clrscr();
k = 3;
m = 4;
change (&k, m);
printf("%d %d",k,m);
}

Ans:- 100, 4.